import java.util.Arrays;Now that you've imported the Arrays library, you can call the sort() method. It's very easy:
Arrays.sort(myArray);Here's some code to try:
import java.util.Arrays;The for loop at the end will print all the values in each position of the array as output. When the code is executed, it gives this result:
public class ArraysTest {
public static void main(String[] args) {
// initialize array
int array[] = {11, 34, 23, 62, 6, 41};
// display all integers before sorting
for (integer : array) {
System.out.println("number: " + integer);
}
// sort array
Arrays.sort(array);
// display all integers after sorting
System.out.println("Sorted array\n");
for (integer int : array) {
System.out.println("number: " + integer);
}
}
}
number: 11As you can see, the array has been sorted in ascending order.
number: 34
number: 23
number: 62
number: 6
number: 41
sorted array
number: 6
number: 11
number: 23
number: 34
number: 41
number: 62
import java.util.Arrays;The compilation and execution of this code gives the following result:
import java.util.Collections;
public class Tri {
public static void main(String[] args) {
// initialize array
int array[] = {8, 77, 15, 24, 46, 13};
// create an array that contains Integer
Integer[] integerArray = new Integer[array.length];
// display all integers before sorting
// copy all values into an array of type Integer
for (int i=0; i < array.length; i++) {
System.out.println("number: " + array[i]);
//instantiate a new Integer
integerArray[i] = new Integer(array[i]);
}
// sort the array, then reverse it
Arrays.sort(integerArray, Collections.reverseOrder());
// display all integers after sorting
System.out.println("Sorted array\n");
for (integer int: integerArray) {
System.out.println("number: " + integer);
}
}
}
number: 8References:
number: 77
number: 15
number: 24
number: 46
number: 13
Sorted array
number: 77
number: 46
number: 24
number: 15
number: 13
number: 8
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